Suppose a bacterium in the gut has a generation time (time to divide) of 16 hours. If it first divides at 4:00, what time will it be when they divide the 80th time afterward?

 The generation time of a bacterium is the time it takes for it to double through cell division. If the generation time is 16 hours, each division results in a doubling of the bacterial population.


Let's calculate the total time it takes for 80 divisions to occur:


Number of divisions = 80


Generation time = 16 hours


Total time = Number of divisions × Generation time


\[ \text{Total time} = 80 \, \text{divisions} \times 16 \, \text{hours/division} \]


\[ \text{Total time} = 1280 \, \text{hours} \]


Now, to find the final time when the 80th division occurs, we add this total time to the initial time:


\[ \text{Final time} = \text{Initial time} + \text{Total time} \]


If the bacterium first divides at 4:00, we can substitute this into the equation:


\[ \text{Final time} = 4:00 \, \text{AM} + 1280 \, \text{hours} \]


To convert hours into a time format, we divide by 24 (since there are 24 hours in a day):


\[ \text{Final time} = 4:00 \, \text{AM} + \frac{1280 \, \text{hours}}{24 \, \text{hours/day}} \]


\[ \text{Final time} = 4:00 \, \text{AM} + 53 \, \text{days and } 8 \, \text{hours} \]


Therefore, the 80th division will occur 53 days and 8 hours after the bacterium first divides, and the final time will be 57:00 (5:00) AM.

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